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If the vector equation of a line is ba...

If the vector equation of a line is
`barr=i+j+k+mu(2i-3j-4k)` , then the Cartesian equation of the line is

A

`(x+2)/2=(y+2)/4=(z+2)/1`

B

`(x-1)/2=(y-1)/-3=(z-1)/-4`

C

`(x+2)/1=(y+2)/4=(z+2)/1`

D

`(x-1)/2=(y-1)/1=(z-1)/-4`

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