A line passes through the point (3,-2,5) and parallel to the vector `hati+2hatj+hatk` What is the vector equation of the line?

Consider the plane passing through (2, 3, 5) and perpendiular to the vector 4hati+2hatj-3hatk Find the vector equation of the plane

A plane passes through the point (0,1,1) and has normal vector hati+hatj+hatk . Its equation is

Consider the plane passing through (2, 3, 5) and perpendiular to the vector 4hati+2hatj-3hatk Find the cartesian equation of the plane

The equation of the line which passes through the point (1,2,3) and parallel to the vector 3i+2j-2k is

A straight line is passing through (3,8,3) and is parallel to the vector 3hati-hatj+k Show that it is not coplanar with the lines (x+3)/-3=(y+7)/2=(z-6)/4

A straight line is passing through (3,8,3) and is parallel to the vector 3hati-hatj+k .Calculate the shortest distance between these lines (x+3)/-3=(y+7)/2=(z-6)/4 .

A straight line is passing through (3,8,3) and is parallel to the vector 3hati-hatj+k (i) Form its equation

Find the vector and cartesian equations of the planes a) that passes through the point (1,0,-2) and the normal to the plane is hati+hatj-hatk b) that passes through the point (1,4,6) and the normal vector to the plane is hati-2 hatj+hatk

Find the vector equation of the line passing through (1,2,3) and parallel to the planes vecr .(hati-hatj+2 hatk)=5 and vecr .(3 hati+hatj+hatk)=6