Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to x-y+z=0

Find the equation of the plane passing through the line of intersection of the planes 2x-y=0,3z-y=0 and perpendicular to the plane 4x+5y-3z=8

The equation of the plane through the line of intersection of the planes x-y+z+3=0 and x+y+2z+1=0 and parallel to x-axis is a) 2y-z=2 b) 2y+z=2 c) 4y+z=4 d) 4y-2z=3

Find the equation of the plane through the intersection of the planes 3x-y+2z-4=0 and x+y+z-2=0 and the point (2,2,1)

Find the equation of the plane through the point (1,2,3) and perpendicular to the plane x-y+z=2 and 2x+y-3z=5

Find the equation of the plane passing through the intersection of the planes x+y+4z+5=0 and 2x-y+3z+6=0 and contains the point (1,0,0).

Equation of the plane passing through the intersecton of the planes x + y + z = 6 and 2x + 3y + 4z + 5 = 0 and the point (1,1,1) is

The plane x+3y+13=0 passes through the line of intersection of the planes 2x-8y+4z=pand3x-5y+4z+10=0 . If the plane is perpendicular to the plane 3x-y-2z-4=0 , then find p

The equation of the plane passing through the intersection of the planes x+2y-z = 3 and x + y - 3z = 5 and passing through the point (1,-1,0) is