Consider a FCC crystal lattice with anions ‘Q’. If half of the octahedral sites of the lattice are occupied by the.cations ‘P’. Write the formula of the crystal.

In a cubic close packed structure of mixed oxides, the lattice is composed of oxide.ions, one eighth of tetrahedral voids are occupied by divalent cations while one hálf of octahedral voids are occupied by trivalent cations. What is the formula of the oxide

In a cubic lattice, the close packed structure of mixed oxides of the lattice is made up of oxide ion, one eighth of the tetrahedral voids are occupied by divalent ions (X^(2+)) while one half of the octahedral voids are occupied by trivalent ions (Y^(3+)) . What is the formula of the oxide?

A crystal is made of particles X,Y and Z. X forms fcc packing. Y occupies all the octahedral voids of X and Z occupies all the tetrahedral voids of X.If the particles along one body diagonal are removed, then the formula of the crystal would be

An alloy of silver and copper crystallizes in a cubic lattice in which silver atoms occupy the lattice points at the comers of a cube and copper atoms occupy the face centres of the cube. Determine the formula of the compound

The unit cell dimensions of a particular crystal system is given below. a=b=c,alpha=beta=gamma !=90^@ .In a crystalline solid, the atom A are arranged in CCP array and atom B occupy all the octahedral voids and half of the tetrahedral voids. What is the formula of the compound ?

Statement 1: In crystal lattice, the size of the tetrahedral void is larger than an octahedral void. Statement 2: The cations occupy less space than anions in crystal packing.

In a close packed face-centred unit cell, are all lattice positions occupied by 'A' atoms and body-centred octahedral hole is occupied by atom 'B' having appropriate size. Choose the correct statement(s) regarding such crystal.