Graphically explain why a solution obtained by dissolving a non-volatile solue in a volatile solvent, freezes at a lower, temperature than that of pure solvent.

Equimolar solutions of non ionic non volatile solute in the same solvent have

When a solution containing non-volatile solute freezes, which equilibrium would exist?

Show graphically how the vapour pressure of a solvent and a solution of a non volatile solute change with temperature. Show the boiling points of the solvent and the solution in the graph. Which is higher and why?

Graphical representation of solution and a solvent for boiling of 0.1 molal solution of non-volatile compound 'A' is given below : identify the curve for solvent and the curve for solution from the figure

Why is the vapour pressure of a solvent lowered by the ạddition of a non- volatile solute?

A solution of 1 molal concentration of a non volatile solute will have maximum boiling pointelevation when the solvent is

The vapour pressure of pure water at a given temperature is 500 torr. When 0.1 mol of a normal non volatile solute is dissolved in 9.9 moles of water at this temperature, the lowering of vapour presure produced is

The expression to compute molar mass of an ideal non volatile solute M_2 from the depression in freezing point mass of solute m_2, and mass of solvent m_1, is

In the depression of freezing point experiment it is found that (i) The vapour pressure of the solution is less than that of pure solvent (ii) The vapour pressure of the solution is more than that of pure solvent (iii) Only solute molecules solidify at the freezing point (iv) Only solvent molecules solidify at the freezing point