`[NiCl_4]^(2-)` is paramagnetic while `Ni(CO)_4` is diamagnetic though both are tetrahedral.Why?

Cu^(2+) is paramagnetic while Cu^+ Is dlamagnetic. Glve reason.

[Cr(NH3)6]^3+ is paramagnetic while [Ni(CN)4]^2- is' diamagnetic. Explain why?

Assertion : [Fe(CN)_6]^(3-) is weakly paramagnetic while [Fe(CN)_6]^(4-) is diamagnetic. Reason : [Fe(CN)_6]^(3-) has +3 oxidation state while [Fe(CN)_6]^(4-) has +2 oxidation state.

Listen the following conversation. Student A: [Ni(CO)_4] Is diamagnetic since it undergoes sp^3 hybridisation. Student B: [Ni(Cl)_4]^(2-) is also diamagnetic as it also undergoes sp^3 hybridisation. Do you agree with the above conversation? Justify your answer.

[Ni(CN)_4]^(2-) has square planar structure and it is diamagnetic. Identify the ligand in the mentioned complex

The magnetic behaviour of a complex can be expained on the basis of VB theory [CO(NH_3)_6)]^(3+) is a diamagnetic complex and [CoF_6]^3- is a paramagnetic complex.Substantiate the above statement using VB theory.

Explain on the basis of V.B, theory that [Ni(CN)_4]^(2-) ion with square planar structure is diamagnetic and the [NiCl_4]^2- ion with tetrahedral geometry is paramagnetic.

Assertion : [Ni(CN)_4]^(2-) is square planar and diamagnetic. Reason : It has no unpaired electrons due to presence of strong ligand.