`(x-1)/(x^2+5x` - `(x+1)/(x^2-25`

(x-1) / (2x + 1) + (2x + 1) / (x-1) = (5) / (2), x! =-(1) / (2), 1

If y=tan^(-1)((4x)/(1+5x^(2)))+tan^(-1)((2+3x)/(3-2x)) , then (dy)/(dx) is equal to a) (5)/(1+25x^(2)) b) (1)/(1+25x^(2)) c)0 d) (5)/(1-25x^(2))

Solve for x (1)/( 2x -3) + (1)/(x -5) =1," " x ne 3/2,5

Solve : (2x^2 - 3x+1) (2x^2 + 5x + 1) = 9x^2 .

If x=3 and y=-1, find the values of each of the using identity: ((5)/(x)+5x)((25)/(x^(2))-25+25x^(2))

If y = tan^-1 (4x)/(1+5x^2) + tan^-1(2+3x)/(3-2x) , prove that dy/dx = 5/(1+25x^2)

If x-(1)/(x)=1 , then the value of (x^(4)-(1)/(x^(2)))/(3x^(2)+5x-3) is