For the equilibrium, `PCl_(5(g)) rarr PCl_(3(g)) + Cl_(2(g)) , `(K = 1.8x10^-7)`. `DeltaG^0` for the reaction at 298K?

Assume that the reaction given below is at equilibrium. PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) , DeltaH = 124.0 Kjmol^-1 . Explain, how the following changes influence this equilibrium. increase in pressure

Assume that the reaction given below is at equilibrium. PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) , DeltaH = 124.0 Kjmol^-1 . Explain, how the following changes influence this equilibrium. increase in temperature.

Assume that the reaction given below is at equilibrium. PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) , DeltaH = 124.0 Kjmol^-1 . Explain, how the following changes influence this equilibrium. Addition of neon gas at constant volume.

Consider the equilibrium, PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) What happens to the above equillibrium when an inert gas is added at constant pressure? Justify.

The K_c for the following reaction. PCl_(5(g)) harr PCl_(3(g)) + Cl_2(g) , H = 124.0 kJ mol^-1 is 8.3xx10^14 .What is the value of Kc for the reverse reaction at the same temperature?

The equilibrium constant for the equilibrium PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) at a particular temperature is 2 xx 10^(-2)" mol dm"^(-3) . The number of moles of PCI_(5) that must be taken in a one-litre flask at the same temperature to obtain a concentration of 0.20 mol of chlorine at equilibrium is