Consider the function `f:R rarr R` defined by `f(x)=|x-1|`.
Is `f(2)=f(0)`,why?

Consider the function f:R rarr R defined by f(x)=|x-1| . Draw the graph of f(x).

Consider the function f:R rarr R defined by f(x)=|x-1| .(iii)If g(x)=|x+1| ,find (f+g) and (f-g).

Consider the function f:R rarr R defined by f(x)=|x-2| (ii)Complete the following table.

Consider the function f:R ---- R defined by f(x)=|x-2| (i)Prove that f(x)={(x-2,xge2),(2-x,x<2) }.

Let A = R - {-3} and B = R - {1} Consider the function f : A rarr B defined by f(x) = (x-2)/(x-3) . Is f one-one and onto ? Justify your answer.

Consider the function f:RrarrR defined by f(x)=-abs[x] Draw the graph of f.

Consider the function f:R to R defined by f(x)=|x-2| (iii)Draw the graph of f(x).

Let A=R-{3} and B=R-{1} consider the function f:ArarrB defined by f(x)=(x-2)/(x-3) .Is it invertible?Why?

Let A=R-{3} and B=R-{1} Consider the function f:ArarrB defined by f(x)=frac(x-2)(x-3) Is f one-one and onto? Justify your answer.