(i)`tan(A-B)=…….`

(i) Tan (pi/6)=………..

If tanA=18/17 and tanB=1/35 prove that tan(A-B)=1

Prove that tan (13pi)/12=tan (pi)/12 and express tan (pi)/12 in the form of tan(A-B).

If tan(A-B)=1 what is the value of A-B?

Prove that tan((A-B)/2)= (a-b)/(a+b)cot frac(c)(2)

If A+B+C=pi , then tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))+tan((C)/(2))tan((A)/(2)) is equal to a) (pi)/(6) b)3 c)2 d)1

Given that tan(A+B)=(tanA+tanB)/(1-tanAtanB) if A+B+C=0^@ prove that tanA+tanB+tanC=tanAtanBtanC hence prove that tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)

tan((A+B)/(2))="cot"(C)/(2)

In triangle ABC , "tan"(A)/(2),"tan"(B)/(2),"tan"(C)/(2) are in H.P ., then the value of "cot"(A)/(2)xx"cot"(C)/(2) is equal to

Given that tan(A+B)=(tanA+tanB)/(1-tanAtanB) by writing A+B+C=(A+B)+C prove that tan(A+B+C)=(tanA+tanB+tanC-tanAtanBtanC)/(1-(tanAtanB+tanBtanC+tanCtanA)