The position of a particle moving on a straight line path is given by `X=12+18t+9t^2` metres.Find the instantaneous velocity at `t=5s[dx/dt=v]`

The position of a particle moving ona straight line path is given by X=12+18t+9t^2 metres,What is the instantaneous acceleration? [a=(dv)/(dt)=(d^2x)/dt^2)]

If the displacement of a particle Is given by, X = A+ Bt^2 . Find the velocity at t = 2s.

Velocity of a particle in SHM at time t is given by V = sqrt(144 - 16 y^(2)) . Maximum velocity is