The ratio of the number of neutrons present in the two element X and Y is 5:7 and the ratio of mass numbers is 10:13 . Element X attains stable octet configuration by losing two electrons from the fourth shell. Calculate the number of protons , electrons and neutrons present in X and Y.

Explanation

Element X attains stability by losing two electrons from the fourth shell, its atomic number is 20, element is calcium.
`therefore` The mass number of Ca is 40 .
Let the mass number of Y is a .
`therefore 40/a=10/13 rArr a=52`
`therefore` Mass number of Y is 52
Number of neutrons is X is 40-20=20
Let the atomic number of Y be b.
`therefore` The number of neutrons in Y be 52-b
`therefore 20/(52-b)=5/7 rArr 52-b=28 rArr` b=24
`therefore` Element Y.s is atomic number is 24 and number of neutrons in Y is 28.