Sugar, on treating with sulphuric acid, turns to a black coloured mass. The property of sulphuric acid exploited in this process is __________.

Options

A. Acid nature
B. Oxidizing property
C. Dehydrating property
D. Bleaching property

Explanation

To solve the question, we need to identify the property of sulfuric acid that is responsible for the transformation of sugar into a black-colored mass when treated with it. Let's break down the solution step by step.

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- When sugar (sucrose, C12H22O11) is treated with concentrated sulfuric acid (H2SO4), it undergoes a chemical reaction. The sulfuric acid acts on the sugar, leading to a significant change in its composition.

2. **Chemical Equation**:
- The reaction can be represented as follows:
\[ C_{12}H_{22}O_{11} + H_2SO_4 \rightarrow 12C + 11H_2O \]
- In this reaction, the sulfuric acid removes water (H2O) from the sugar, resulting in the formation of carbon (C) and water.

3. **Identifying the Property**:
- The key property of sulfuric acid that facilitates this reaction is its ability to remove water. This characteristic is known as the **dehydrating property**.

4. **Conclusion**:
- Therefore, the property of sulfuric acid exploited in this process is its **dehydrating property**.

### Final Answer:
The property of sulfuric acid exploited in this process is **dehydrating property**.

---