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The average force necessary to stop a ha...

The average force necessary to stop a hammer with momentum p (in N-s) in 0.5 s is :-

A

25 N

B

50 N

C

1.25 N

D

500 N

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(1) = 25, P_(1) = 0, Deltat = 0.05`
`F = (DeltaP)/(Deltat) = 25/(0.05) = 2500/5 = 500 N`
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Knowledge Check

  • The average force necessary to stop a hammer with 50 NS momentum in 0.05 s is

    A
    50 N
    B
    100 N
    C
    500 N
    D
    1000 N

  • The average force necessary to stop a bullet of mass 20 g moving with a speed of 250 m//s , as it penetrates into the wood for a distance of 12 cm is

    A
    `2.2xx10^(3)N`
    B
    `3.2xx10^(3)N`
    C
    `4.2xx10^(3)N`
    D
    `5.2xx10^(3)N`

  • If a force 200N acts on a body, the change in momentum is 100 kg m/s. What is the time for which the force acts on th body?

    A
    1 sec
    B
    0.75 sec
    C
    0.5 sec
    D
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