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The average force necessary to stop a ha...

The average force necessary to stop a hammer with momentum p (in N-s) in 0.5 s is :-

A

25 N

B

50 N

C

1.25 N

D

500 N

Text Solution

Verified by Experts

The correct Answer is:
D
`P_(1) = 25, P_(1) = 0, Deltat = 0.05`
`F = (DeltaP)/(Deltat) = 25/(0.05) = 2500/5 = 500 N`
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