The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘ a ’ is `3 : 2`. The value of ‘ a ’ is ( g - Acceleration due to gravity of the earth)

Options

A. (3/2) g
B. g
C. (2/3) g
D. g/3

Answer

D

Explanation

Weight of man in stationary lift is mg.

mg - N = ma [Newton's II law for man]
`rArr N =m(g-a)`
Weight of man in moving lift is equal to N
`(mg)/(m(g-a)) = 3/2 rArr a =g/3`