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A ball weighing 50g hits a hard surface ...

A ball weighing 50g hits a hard surface normally with a speed of 25m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.05s .The average force exerted by the surface on the ball is?

A

100 N

B

10 N

C

1 N

D

4 N

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaP = 2mv`
`=2 xx 10 xx 10^(-3) xx 5`
`=10^(-1)`
`Deltat = 10^(-2)`
`F = (DeltaP)/(Deltat)`
` = 10^(-1)/10^(-2) = 10 N`
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