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The 50kg homogenous smooth sphere rests ...

The 50kg homogenous smooth sphere rests on the `30^(@)` incline A and bears against the smooth vertical wall B.Calculate the contact forces at A and B.

A

`N_(A)= 1000/sqrt(3) N, N_(B) = 500/sqrt(3)` N

B

`N_(A) = 1000/sqrt(3) N, N_(B) = 1000/sqrt(3) N`

C

`N_(A) = 500/sqrt(3) N, N_(B) = 500/sqrt(3) N`

D

`N_(A) = 500/sqrt(3) N, N_(B) = 1000/sqrt(3) N`

Text Solution

Verified by Experts

The correct Answer is:
A


`mg - N_(A) cos 30=0` [Eqluilibrium in vertical direction]
`rArr N_(A) = (mg)/(cos 30^(@))`
`rArr N_(A)= 1000/sqrt(3) N`
`N_(B)- N_(A) sin 30 =0` [Equilibrium in horizontal]
`rArr N_(B) = N_(A) sin 30`
`rArr N_(B) = 1000/sqrt(3) xx 1/2`
`rArr N_(B) = 500/sqrt(3) N`
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