In the figure, the blocks A,B and C of mass m each have accelerations `a_(1),a_(2)` and `a_(3)` respectively. `F_(1)` and `F_(2)` are external forces of magnitude 2mg and mg respectively.

Options

A. `a_(1) = a_(2) = a_(3)`
B. `a_(1) gt a_(2) gt a_(3)`
C. `a_(1) = a_(2) , a_(2) gt a_(3)`
D. `a_(1) gt a_(2), a_(2) = a_(3)`

Answer

B

Explanation

`a_(1) = (2mg + mg)/m, a_(2) = ((2m-m)g)/(2m+m), a_(3)=0`
`a_(1) =g, a_(2) = g/3`
So, `a_(1) gt a_(2) gt a_(3)`