The bulk modulus of a spherical object is `B` if it is subjected to uniform pressure `p`, the fractional decrease in radius is:

Options

A. `(B)/(3P)`
B. `(3P)/(B)`
C. `(P)/(3B)`
D. `(P)/(B)`

Answer

C

Explanation

`B= (P)/(-(Delta v)/(v))` ..(i)
where B= bulk modulus
Volume of spherical body `V = (4)/(3) pi R^(3)`
Fractional change in volume `(Delta V)/(V) =(3Delta R)/(R )`
Substituting the value of `(Delta V)/(V)`
`B= (P)/(-(3Delta R)/(R ))`
`(Delta R)/(R )= (-) (P)/(3B)` where (-ve) sign is decrease in radius