Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?

Options

A. `(M)/(sigma- rho)`
B. `(sigma - rho)/(M)`
C. `M [(1)/(rho)- (1)/(sigma)]`
D. `(1)/(M) [(1)/(sigma)- (1)/(rho)]`

Answer

C

Explanation

Volume of ice `= (M)/(rho)`, volume of water `= (M)/(sigma)`
`therefore` Change in volume `= (M)/(rho)= M [(1)/(rho)- (1)/(sigma)]`