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For a gas molecule with 6 degrees of fre...

For a gas molecule with 6 degrees of freedom,the law of equipartion of energy gives the following relation between the molecular specific heat `(C_(V))` and gas constant (R)

A

` C_V = ( R ) /(2) `

B

` C_ V= R `

C

` C_ V = 2R `

D

` C_V = 3R `

Text Solution

Verified by Experts

The correct Answer is:
D
Specific heat at constant volume (CV) and degreee freedom
` C_V = (fR)/( 2) = ( 6R)/(2) " " therefore f= 6`
` C_ V = 3R `
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