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10 moles of an ideal monoatomic gas at 1...

10 moles of an ideal monoatomic gas at `10^(@)C` are mixed with 20 moles of another monoatomic gas at `20^(@)C`. Then the temp. of the mixture is

A

` 15.5^(@)C `

B

` 15 ^(@) C`

C

` 16^(@)C `

D

` 16.6^(@) C`

Text Solution

Verified by Experts

The correct Answer is:
D
` T_m = (n_1T_1+ n+2T_2)/(n_1+n_2) `
` (10 xx 10 +20 xx 20 )/(10 + 20) = ( 500)/(3) = 16.6^(@) C`
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