Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

Options

A. `45^(@)`
B. `90^(@)`
C. `60^(@)`
D. `30^(@)`

Answer

B

Explanation

When a bigger pendulum of `T_(1)=5T//4` complete one vibration, the smalle pendulum will complete 5/4 vibration. It means the smaller pendulum will be leading, the bigger pendulum by phase T/4 sec = `(pi)/(2)` rad = `90^(@)`