A 10 kg metal block is attached to a spring constant `1000 Nm^(-1)`. A block is displaced from equilibrium position by 10 cm and released. The maximum acceleration of the block is

Options

A. `10ms^(-2)`
B. `100ms^(-2)`
C. `200ms^(-2)`
D. `0.1ms^(-2)`

Answer

A

Explanation

In spring SHM, the restoring force is proportional displacement,
`F=-momega^(2)y....(i)`
`F=-ky…..(ii)`
Where, k = force constant of the spring Comparing the both equation, we get
`omega^(2)=(k)/(m)impliesomega=sqrt((k)/(m))=sqrt((1000)/(10))impliesomega=10" rad/s"`
Acceleration in SHM is given by
`a_(max)=-omega^(2).y`
`=-10^(2)xx(0.1)=-10m//s^(2)`