In figure `S_(1)` and`S_(1)` are identical springs. The oscillation frequency of the mass `m` is `f`. if one spring is removed, the frequency will become

Options

A. f
B. 2f
C. `sqrt(2)`f
D. `(f)/(sqrt(2))`

Answer

D

Explanation

Effective spring constant, `k=2k`
Frequency of oscillation, `f=(1)/(2pi)sqrt((2k)/(m))`
When one spring is removed, then spring constant = k New frequency of oscillation will be
`f'=(1)/(2pi)sqrt((k)/(m))=(f)/(2)`