The electron in a hydrogen atom is moving with a speed of `2*3xx10^6ms^-1` in an orbit of radius `0*53oversetoA`. Calculate the magnetic moment of revolving electron.

Options

A. `9.75 xx 10^(-21) Am^(2)`
B. `9.75 xx 10^(-20) Am^(2)`
C. `8.75 xx 10^(-24) Am^(2)`
D. `9 xx 10^(-24) Am^(2)`

Answer

D

Explanation

Equivalent current
`I =e/(2piv//v) = (ev)/(2pir)`
`=(1.6 xx 10^(-29) xx 2.3 xx 10^(6))/(2 xx 3.14 xx 0.53 xx 10^(-10))`
`=1.05 xx 10^(-3) A`
`M = 1.105 xx 10^(-3) xx 3.14 xx (0.53 xx 10^(-10))^(2)`
`M = 9.75 xx 10^(-24) Am^(2)`