The earth's magnetic field at a certain place has a horizontal component 0.3 Gauss and the total strength 0.5 Gauss. The angle of dip is

Options

A. `tan^(-1) 3/4`
B. `sin^(-1) 3/4`
C. `tan^(-1)4/3`
D. `sin^(-1) 3/5`

Answer

C

Explanation

`B_(v) = sqrt(B^(2) -B_(H)^(2)) = sqrt((0.5)^(2) - (0.3)^(2))`
`B_(v) =0.4`
Now, `tan phi = B_(v)/B_(H) = 0.4/0.3 = 4/3`
`phi = tan^(-1) (4/3)`