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A bar magnet suspended freely in a unifo...

A bar magnet suspended freely in a uniform magnetic field is vibrating with a time period of 3s. If the field strength is increased to 4 times of the earlier field strength, then the time period (in second) will be

A

12

B

6

C

1.5

D

0.75

Text Solution

Verified by Experts

The correct Answer is:
C

`T = 2pi sqrt(1/(MB))`
`T prop 1/sqrt(B)`
`T_(1)/T_(2) = sqrt(B_(1)/B_(2)) rArr 3/T_(2) = sqrt(4/1)`
`T_(2) = 1.5` sec
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