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A 250-turns recantagular coil of length...

A 250-turns recantagular coil of length 2.1 cm and width 1.25 cm carries a current of `85 muA` and subjected to magnetic field of strength `0.85 T`. Work done for rotating the coil by `180^(@)` against the torque is

A

`4.55 muJ`

B

`2.3 muJ`

C

`1.15 muJ`

D

`9.1 muJ`

Text Solution

Verified by Experts

The correct Answer is:
D
Work =` MB [ cos theta_(1) - cos theta_(2)]`
`=MB[cos 0^(@) - cos 180^(@)]`
`=NiAB [1-(-1)]`
`=2NiAB`
`=2 xx 250 xx 85 xx 10^(-6) xx 2.1 xx 10^(-2) xx 1.25 xx 10^(-2) xx 0.85`
`= 9.12 muJ`
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