The electron in a hydrogen atom makes a transition from `n=n_(1)` to `n=n_(2)` state. The time period of the electron in the initial state `(n_(1))` is eigh times that in the final state `(n_(2))`. The possible values of `n_(1)` and `n_(2)` are

Options

A. `n_(1)=4,n_(2)=2`
B. `n_(1)=8,n_(2)=2`
C. `n_(1)=8,n_(2)=1`
D. `n_(1)=6,n_(2)=2`

Explanation

In the nth orbit, let m=radius and vn= speed of electron.
Time period `T_(n)=(2pir_(n))/(V_(n))prop(r_(n))/(V_(a))`
Now `r_(n)prop n^(2)` and `V_(n)prop1/n`
`:.(r_(n))/Vpropn^(3)` or `T_(n)propn^(3)`
Here `8=((n_(1))/(n_(2)))^(3)implies(n_(1))/(n_(2))=2impliesn_(2)=2n_(2)`