If an orbital electron of the hydrogen atom jumps from the groud state to a higher energy state, its orbital value where its velcoity is reduced to half its initial value.. If the radius of the electron orbit in the ground state is `r`, then the radius of the new orbit would be:

Options

A. 2r
B. 4r
C. 8r
D. 16r

Explanation

Since speed reduces to half KE reduced to
`1/4` th `impliesn=2`
`mvr=(nh)/(2pi)`
`mv_(0)r=1,h/(2pi)` ……I
`m(v_(0))/2r'=2 . h/(2pi)`…II
`r'=4r`