The decay constant of a radioactive sample is `'lambda'`. The half-life and mean life of the sample are respectively a)`1/lamda,("in"2)/lamda` b)`("in"2)/lamda,1/lamda` c)`"in"2,1/lamda` d)`lamda/("in"2),1/lamda`

Options

A. `1/(lamda)` and d`(log_(e)2)/(lamda)`
B. `(log_(e)2)/(lamda)` and `1/(lamda)`
C. `(lamda)/(log_(e)2)` and `1/(lamda)`
D. `(lamda)/(log_(e)2)` and `2lamda`

Explanation

If decay constant is `lamda`
Mean life `tau=1/(lamda)`
and half life
`=(log_(e)2)/(lamda)`