In a radioactive reaction `""_(92)X^(232)to82Y^(212)`, the number of `alpha`- particles emitted is

Options

A. 7
B. 6
C. 5
D. 4

Explanation

To determine the number of alpha particles emitted in the radioactive reaction \( _{92}^{232}X \rightarrow _{82}^{212}Y \), we can follow these steps:

### Step 1: Identify the Change in Atomic Number
- The atomic number of \( X \) is 92, and the atomic number of \( Y \) is 82.
- The change in atomic number is calculated as:
\[ \Delta Z = Z_X - Z_Y = 92 - 82 = 10 \]
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