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The equation 4""(1)H^(1)to""(2)He^(4++)+...

The equation `4""_(1)H^(1)to""_(2)He^(4++)+Ze^(+)+26` MeV represents:

A

`gamma` - decaya

B

`beta`- decay

C

Fission

D

Fusion

Text Solution

AI Generated Solution

To analyze the equation \( 4_{1}H^{1} \rightarrow 2He^{4++} + Ze^{+} + 26 \text{ MeV} \), we need to break down the components of the reaction step by step. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The left side of the equation shows \( 4_{1}H^{1} \), which represents four hydrogen nuclei (protons). - The right side shows \( 2He^{4++} \), which represents a helium nucleus (2 protons and 2 neutrons). - The term \( Ze^{+} \) indicates the emission of a positron (the antiparticle of an electron). ...
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