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When a uranium isotope ""(92)^(235)U is ...

When a uranium isotope `""_(92)^(235)U` is bombared with neutron, it generates `""_(36)^(89)Kr` three neutrons and

A

`""_(40)^(91)Zr`

B

`""_(36)^(101)Kr`

C

`""_(36)^(103)Kr`

D

`""_(56)^(144)Br`

Text Solution

AI Generated Solution

To solve the problem of the nuclear reaction involving the uranium isotope \( \text{ }_{92}^{235}\text{U} \) being bombarded with a neutron, we need to identify the missing product of the reaction. Let's break down the steps to find the unknown element. ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: The reaction can be represented as: \[ \text{ }_{92}^{235}\text{U} + \text{ }_{0}^{1}\text{n} \rightarrow \text{ }_{36}^{89}\text{Kr} + 3 \text{ }_{0}^{1}\text{n} + X ...
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Knowledge Check

  • If ""^(235)U is bombarded with neutron, the atom will split into

    A
    Sr+Pb
    B
    Cs+Ra
    C
    Kr+Cd
    D
    Ba+Kr
  • Uranium ._(92)U^(235) on bombardment with slow neutrons produces

    A
    Deutrons
    B
    Fusion reaction
    C
    Fission reaction
    D
    Endothermic reaction
  • If U^(235) is bombarded with neutrons, atom will split into

    A
    `Sr + Pb`
    B
    `Cs + Rb`
    C
    `Kr + Cd`
    D
    `Ba + Kr`
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