If an electron in a hydrogen atom jumps from the `3rd` orbit to the `2nd` orbit, it emits a photon of wavelength `lambda`. When it jumps form the `4th` orbit to the `3dr` orbit, the corresponding wavelength of the photon will be

Options

A. `20/7lamda`
B. `20/13lamda`
C. `16/25lamda`
D. `9/16 lamda`

Explanation

`1/(lamda)=v=RZ^(2)[1/(n_(2)^(2))-1/(n_(1)^(2))]`
Transition `3to2implies` Wavelength `lamda`
Transition `4to3implies` Wavelength `lamda'=?`
`(1/(lamda)=RZ^(2)(1/(2^(3))-1/(3^(2))))/(1/(lamda')=RZ^(2)(1/(3^(2))-1/(4^(2))))implies(lamda')/(lamda)=20/7implieslamda'=(20lamda)/7`