The energy liberated per nuclear fission is 200 MeV.If `10^(20)` fissions occur per second the amount of power produced will be

Options

A. `2xx10^(22)W`
B. `32xx10^(8)W`
C. `16xx10^(4)W`
D. `5xx10^(31)W`

Explanation

To solve the problem of calculating the power produced from nuclear fission, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Energy Released per Fission**:
The energy liberated per nuclear fission is given as 200 MeV (Mega electron volts).

2. **Convert MeV to Joules**:
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