The molecules of a given mass of a gas have rms velocity of `200 m//s at 27^(@)C and 1.0 xx 10^(5) N//m_(2)` pressure. When the temperature and pressure of the gas are respectively `127^(@)C and 0.05 xx 10^(5) Nm^(-2)`, the rms velocity of its molecules in `ms^(-1)` is

Options

A. `100sqrt(2)`
B. `400/(sqrt(3))`
C. `(100sqrt(2))/3`
D. `100/3`

Explanation

`Vprop sqrt(T)`
`toV/200=sqrt(400/300)`
`toV=(200(2))/(sqrt(3))impliestoV=400/(sqrt(3))ms^(-1)`