Glucose is taken in a test tube and acted upon by hexokinase enzyme. Resulting substrate is glucose-6-phosphate. This isolated metabolic reaction is:

Options

A. Occurring in test tube which can be considered as living reaction
B. Considered to be in vivo
C. Considered to be in vitro and living reaction.
D. Considered as non-living

Answer

**Step-by-Step Solution:**

1. **Understanding the Reaction**: The reaction involves glucose being converted into glucose-6-phosphate by the enzyme hexokinase. This is a key step in the metabolic pathway of glucose utilization.

2. **Identifying the Environment**: The reaction is taking place in a test tube, which indicates that it is being conducted outside of a living organism.

3. **Defining Terms**:
- **In Vivo**: Refers to processes or reactions occurring inside a living organism.
- **In Vitro**: Refers to processes or reactions occurring outside of a living organism, typically in a controlled environment like a test tube.
- **Living Reaction**: Generally refers to biochemical reactions that occur in living organisms.

4. **Analyzing the Context**: The video transcript indicates that even though the reaction is occurring in vitro (in a test tube), it can still be considered a living reaction if it is functioning efficiently and completely, similar to how it would in vivo.

5. **Conclusion**: The isolated metabolic reaction of glucose being converted to glucose-6-phosphate by hexokinase in a test tube is classified as a "living reaction" despite being performed in vitro. This is because the enzymatic activity is complete and efficient in this controlled environment.

**Final Answer**: The isolated metabolic reaction is considered a living reaction, even though it occurs in vitro.

---