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If sec theta= a/b, b ne 0, then (1-tan^2...

If `sec theta= a/b, b ne 0`, then `(1-tan^2 theta)/(2-sin^2 theta)`= ?
यदि `sec theta= a/b, b ne 0`, तो `(1-tan^2 theta)/(2-sin^2 theta)`= ?

A

`(a^2(2b^2+a^2))/(b^2(a^2-b^2))`

B

`(a^2(2b^2+a^2))/(b^2(a^2+b^2))`

C

`(a^2(2b^2-a^2))/(b^2(a^2+b^2))`

D

`(b^2(2b^2-a^2))/(a^2(a^2+b^2))`

Text Solution

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