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In `triangle ABC`, `angle C=90^@`, Points P and Q are on the sides AC and BC, respectively, such that AP :PC =BQ: QC=1:2 Then `(AQ^2+BP^2)/(AB^2)` is equal to:
`triangle ABC` में `angle C=90^@`, बिंदु P और Q क्रमशः AC और BC पर बिंदु इस प्रकार है की AP :PC =BQ: QC=1:2 तो `(AQ^2+BP^2)/(AB^2)` = ?

A

`(4)/(9)`

B

`(4)/(3)`

C

`(13)/(9)`

D

`(8)/(3)`

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