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A circle is inscribed in `triangle ABC`, touching AB, BC and AC at points P, Q and R respectively. If AB-BC = 4cm, AB-AC = 2cm and the perimeter of `triangle ABC = 32cm`, then PB+AR is equal to :
/ एक वृत्त त्रिभुज ABC के भीतर स्थित है जो AB, BC और AC को क्रमशः बिंदु P, Q और R पर स्पर्श करता है | यदि AB-BC =4 सेमी, AB-AC =2 सेमी और त्रिभुज ABC का परिमाप = 32 सेमी है, तो PB+AR का मान ज्ञात करें

A

`33/5` cm

B

13 cm

C

`38/3` cm

D

12 cm

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