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The expression of (cottheta+"cosec"the...

The expression of `(cottheta+"cosec"theta-1)/(cottheta-"cosec"theta+1)` is equal to

A

`(1+cos theta)/(sin theta)`

B

`(1-cos theta)/(sin theta)`

C

`(cot theta-1)/(cosec theta)`

D

`(cot theta+1)/(cosec theta)`

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