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If x = a cos theta + b sin theta and y=a...

If `x = a cos theta + b sin theta` and `y=a sin theta-b cos theta`, the value of `x^2+y^2` is:
यदि `x = a cos theta + b sin theta` तथा `y=a sin theta-b cos theta` है, तो `x^2+y^2` का मान ज्ञात करें |

A

`x^2+y^2=a^2-b^2`

B

`x^2+y^2=a^2+b^2`

C

`x^2/a^2+y^2/b^2=1`

D

`x^2/y^2+a^2/b^2=1`

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