Average of n numbers is a. The first number is Increased by 2, second one is increased by 4, the third one is Increased by 8 and so on. The average of the new numbers Is:

Options

A. `a+(2^(n-1))/n`
B. `a+(2^n-1)/n`
C. `a+(2^(n+1)-1)/n`
D. `a+2(2^n-1)/n`