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Sin(A+B) & Sin(A-B)...

Sin(A+B) & Sin(A-B)

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Trigonometric ratios OF compound angle Sin(A+B) || Sin(A-B) || Cos(A+B) || Cos(A-B) and problem on these

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

Standard Formula sin(A+B) || sin(A–B) || cos(A+B) || cos(A–B)

19.Prove that sin (A + B) sin (AB) + sin (B + C) sin (BC) + sin (C + A) sin (CA) = 0

sin A sin (A + 2B) sin B sin (B + 2A) = sin (AB) sin (A + B)

sin A sin (A + 2B) -sin B sin (B + 2A) = sin (AB) sin (A + B)

In any triangle ABC , prove that a sin A-b sin B -=c sin (A-B) .