Tan(A±B) & Cot(A±B)

Prove that: (sinA+sinB)/(sinA-sinB) = tan(A+B)/(2). Cot(A-B)/(2)

If csc A+sec A=csc B+sec B, prove that: tan A tan B=cot(A+B)/(2)

tan(A+B)=p,tan(A-B)=qthen cot2B=

In a DeltaABC, tan ""1/2 (A+B) . Cot""1/2(A-B) is equal to

Ifcos ecA+sec A=cos ecB+sec B, prove that tan A tan B=(cot(A+B))/(2)

Prove that: (s in A+s in B)/(s in A-s in B)=tan((A+B)/(2))cot((A-B)/(2))

Prove that (1-cos A+cos B-cos(A+B))/(1+cos A-cos B-cos(A+B))=tan((A)/(2))cot((B)/(2))

In DeltaABC,cot.(A+B)/(2).tan.(A-B)/(2) =

In triangle ABC, if |[1,1,1], [cot (A/2), cot(B/2), cot(C/2)], [tan(B/2)+tan(C/2), tan(C/2)+ tan(A/2), tan(A/2)+ tan(B/2)]| then the triangle must be (A) Equilateral (B) Isoceless (C) Right Angle (D) none of these

If tan A - tan B =x and cot B - cot A=y, then: cot(A-B)=