Sin3A, Cos3A & Tan3A Formulae

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(sin A sin2A + sin3A sin6A) / (sin A cos2A + sin3A cos6A) = tan5A

(sin A sin2A + sin3A sin6A + sin4A sin13A) / (sin A cos2A + sin3A cos6A + sin4A cos13A) = tan9A

cos ^ (3) A sin3A + sin ^ (3) A cos3A = k sin4A rArr k =

If sin A+3cos A=0 ,then tan2A equals to

If sin A,cos A,tan A are in GP, then cos^(3)A+cos^(2)A is equal to -

Prove that: (sin5A-sin3A)/(cos5A+cos3A)=tan A(sin A+sin3A)/(cos A+cos3A)=tan2A

(sin A+sin3A)/(cos A+cos3A)=tan2A

If tan A=(1-cos B)/(sin B) , then tan3A is equal to

sin^(3)A sin3A+cos^(3)A cos3A=cos^(3)(2A)