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Prove that the number 4^n, n being a nat...

Prove that the number `4^n`, n being a natural number, can never end with the digit 0.

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Can the number 6^(n),n being a natural number, end with the digit 5? Give reason.

Can the number 9^(n) , n being a natural number, end with the digit 5 ? Give reasons

Show that any number of the form 4^(n),n ne N can never end with the digit 0.

Prove that there is no natural number for which 4^(n) ends with the digit zero.

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Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.

Consider the numbers 4^(n) , where n is a natural number. Check whether there is any value of n for which 4^(n) ends with the digit zero.

AGRAWAL PUBLICATION-REAL NUMBERS-EXAMPLE
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  2. Using prime factorisation method, find the HCF and LCM of 210 and 175.

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  16. Prove that sqrtp+sqrtq is irrational, where p and q are primes.

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