For a rhombus ABCD prove the following:
`4AB^2 = AC^2 + BD^2`.

For a rhambus ABCD , prove that 4 AB ^(2) = AC^(2) + BD^(2)

In a rhombus ABCD, prove that AC^(2) + BD^(2) = 4AB^(2)

In rhombus ABCD,show that 4AB^(2)=AC^(2)+BD^(2)

In a rhombus prove that sum of squares of sides is equal to sum of square of diagonals or, In a rhombus ABCD prove that AB^(2)+BC^(2)+CD^(2)+DA^(2)=AC^(2)+BD^(2)

In a Delta ABC, /_ B is an acute-angle and AD bot BC . Prove that: AB^2 + CD^2 = AC^2 + BD^2

Let ABCD be a parallelogram. Let m and n be positive integers such that n lt mlt 2n . Let AC =2 mn and BD =m^2 - n^2 . Let AB = (m^2 + n^2) /2 . Statement I AC gt BD Statement II ABCD is a rhombus. Which one of the following is correct in respect of the above statements ?

Let ABCD be a parallelogram. Let m, n be positive integers such that n lt m lt 2n. Let AC = 2mn and BD=m^(2)-n^(2) . Let AB=(m^(2)+n^(2))//2 . Statement - I : AC gt BD Statement - II : ABCD is a rhombus. Which one of the following is correct in respect of the above statements ?

In a Delta ABC , angleB is an acute-angle and AD bot BC Prove that : (i) AC^(2) = AB^(2) + BC^(2) - 2 BC xx BD (ii) AB^(2) + CD^(2) = AC^(2) + BD^(2)

In a quadrilateral ABCD prove that AB^(2)+BC^(2)+CD^(2)+DA^(2)=AC^(2)+BD^(2)+4PQ^(2) where P and Q are middle points of diagonals AC and BD.

In the given figure if AD bot BC prove that AB^(2)+CD^(2)= BD^(2) +AC^(2)